18x^2+14x-10=0

Solution for 18x^2+14x-10=0 equation:

18x^2+14x-10=0

a = 18; b = 14; c = -10;
Δ = b2-4ac
Δ = 142-4·18·(-10)
Δ = 916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{916}=\sqrt{4*229}=\sqrt{4}*\sqrt{229}=2\sqrt{229}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{229}}{2*18}=\frac{-14-2\sqrt{229}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{229}}{2*18}=\frac{-14+2\sqrt{229}}{36}
$